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See what's wrong in this image? I had heard the new D800 suffered from lock-up problems, but now my D7000 seems to have similar problems. Anyone else have this also?
Update: Even though I have not been able to reproduce the problem, I suspect it is related to the SD cards. Removing and reinserting the battery did not help. Removing the memory cards did! I have since reset the shooting settings and the problem has not presented itself again.
Update2: I was able to switch the LCD light on and off when the D7000 was locked-up. Also, information in the viewfinder was still visible. When half-pressing the shutter button, the AF-point lighted red as usual, but the image did not focus. Strange!
Bit greedy to have it to myself. After finding the Christmas serving plate, it wasn't all that brilliant anyway. Aldi's special edition spicy chicken sourdough
My fangirl problem :
Whn you never get to spend time with your boyfriend because he`s on tour .
Lol , silly Andy Biersack , come back !
My painting 1974, Black & White. Abstract realisation of a medicinal problem, a connatal maldevelopment of the lower spine. Privatbesitz
An Afghan woman in first grade solves a math problem during class in Bamyan, Afghanistan. The classes were made available to Afghan women, many of whom have never attended a class in their lives, by Arzu Studio Hope. Arzu is a nonprofit organization, based out of Chicago, which aims to empower Afghan women through employment and education. Arzu founder, Connie Duckworth, visited the classes and expressed her pride in the Afghan women for their strong desire to improve their quality of life. Duckworth also visited Helmand province in search of possible locations to expand her organization.
El presidente del Partido Popular y candidato a la Presidencia de Cantabria, Ignacio Diego, animó hoy a los 102 candidatos a alcaldes de su formación polÃtica a dar a conocer a los cántabros, municipio por municipio, "la capacidad que tenemos para resolver los problemas de los ciudadanos". Además, Diego apostó por explicar el contenido del programa electoral, cuyo lema es "empleo y buen gobierno", frente al "caos" que han generado regionalistas y socialistas.
En el acto público de presentación de los 102 candidatos del Partido Popular a las alcaldÃas de Cantabria, celebrado en el Auditorium "Los Carabelas" de Santander, Ignacio Diego les pidió hacer "el esfuerzo de la claridad y la transparencia, el esfuerzo del compromiso y del juego limpio". En este sentido subrayó que "tenemos mucho que proponer a los cántabros", por ello apeló a hablar "de lo nuestro".
En referencia a regionalistas y socialistas, el presidente de los populares cántabros y candidato a la Presidencia de Cantabria consideró que hay que dejarles hacer "lo que están haciendo desde hace ya mucho tiempo" y comparó la situación con la final del Campeonato del Mundo de Fútbol. "Dejemos que ellos hagan el papel de Holanda, que se dediquen al patadón, porque han demostrado que no saben hacer otra cosa", subrayó.
En este sentido añadió que el Partido Popular debe dedicarse "a jugar, que sabemos hacerlo, a jugar limpio, a jugar bien, ágil, rápido, a desbordarles una y otra vez y a ganar".
Tras señalar que los cántabros "esperan mucho" del PP y añadir que a esta formación polÃtica le "preocupa Cantabria", Diego señaló que su partido está "en todos y cada uno de los rincones de Cantabria" y trabaja "por todos y cada uno de sus ciudadanos sin ninguna distinción".
"Se acabaron las actitudes del actual Gobierno, se acabó el sectarismo, se acabó el mirar a la gente por su carné, eso ya se acabó y empieza un nuevo tiempo de la mano del Partido Popular", señaló el presidente regional del PP quien añadió que "comienza el tiempo de hacer avanzar Cantabria, los 600.000 cántabros juntos, liderados por un proyecto polÃtico y por un equipo de personas con ganas de transmitir esperanza con soluciones".
Diego aprovechó para recordar su experiencia como alcalde de Astillero, un perÃodo de tiempo del que dijo sentir "añoranza" porque "la polÃtica municipal es la polÃtica cercana, próxima, la polÃtica que te permite conocer a tus vecinos, sus problemas, sus ilusiones, sus esperanzas y satisfacerlas".
"Daros a ellos, porque no hay nada más bonito que concebir un proyecto, compartirle con el equipo, poner a trabajar a los compañeros de trabajo que van a ser los funcionarios de los ayuntamientos y hacer que junto a ellos se convierta el proyecto en una realidad para los vecinos. No hay satisfacción más grade", señaló Diego.
Diego pidió a sus candidatos que conviertan su apego a los municipios en "hechos, en empleo, en soluciones y calidad de vida para los vecinos" y consideró que para ello cuentan con la "credibilidad que otros han perdido", por lo que auguró un crecimiento en votos. "Pueblo a pueblo, municipio a municipio, todos vais a crecer en votos, se espera eso de vosotros y sois responsables de ello, vais a hacer crecer al Partido Popular mucho más allá de lo que se espera, vais a ser la gran sorpresa de Cantabria en estas elecciones", señaló.
Con anterioridad a Ignacio Diego, en el acto intervinieron también, además del candidato a la reelección como alcalde de Santander, Iñigo de la Serna, los candidatos a las alcaldÃas de Santoña, Milagros Rozadilla; Villaescusa, Almudena Gutiérrez; Limpias, Germán Alquegui, y Campoo de Yuso, Leticia López.
Todos ellos coincidieron en señalar la necesidad de un cambio de gobierno en Cantabria con Diego como presidente, con el fin de que, como dijo la candidata Almudena Gutiérrez, "los ayuntamientos puedan levantar cabeza".
My handlebar bag presses the barcon shifter housing out of the way in a really awkward and ugly shape. This bike doesn't have downtube bosses. There are two options: Run the housing all the way under the bar tape...or....wait and see...
by Alfredo Fernandes
Alfi Art Production, Divar
41st Tiatr Competition A group of Kala Academy supported by TAG
13.10.2015
Ciena Furtado and Jovienne Fernandes
more here
joegoauk-tiatr.blogspot.in/2015/10/41st-tiatr-competition...
Another archive I found. I drew this in 1992!!
Back then I remember the medium I used was something that was called 'magic pen'. The ink smeared and faded over the years. The black ink I believe was from a waterproof Pilot black pen, which was my favourite drawing tool.
Blogged on : designerinpajamas.wordpress.com/2009/04/08/old-work/
Go North East's 8327 (NK11 GWY), Optare Versa V1110/Optare Versa, carrying its "SimpliCity" branding, pictured on Ryhope Road, Sunderland, while working "SimpliCity" service 42 to City Centre. 06/05/13
Due to a problem at the DVLA with registering this vehicle, it was allocated a new registration mark (NK11 GWY) prior to entering service and surrendered its original registration mark (NK11 FXL).
On the last weekend of November, close to 600 people gathered at the Catholic Junior College Performing Arts Centre for a retreat led by Fr Laurence Freeman OSB, organised by The World Community for Christian Meditation (WCCM) Singapore.
The topic was the 8 big problems of life.
The swans have been sitting tight for a number of weeks now but today Bonnie got up to turn the eggs for long enough for us to get a glimpse. There appear to be at least 4 eggs in there - fingers crossed for safe arrival of the cygnets, as recent goslings and some of the ducklings have not survived for long. Not sure if they have a mink problem again this year.
We often magnify our problems by denial ...recently one of my friend had lots of problem with another friend of mine because he was not able to accept the irrational behavior of other friend ... and yesterday he told that he found his life had changed because he accepted the fact that other friend is usually irrational ... sometimes accepting things helps ...
So I've been tagged in the flickr tagging game, where you are supposed to post the 5th photo of your 5th folder. This posed some interesting problems, mainly in terms of determining which folder is the 5th, given that the folders on your computer are arranged in an n-ary tree structure. There are a multitude of tree traversal algorithms, and the game does not specify which algorithm to use. Hence, the rules of the game are woefully underspecified. Below are some of the options for traversing a tree structure. Personally, I selected a breadth first search.
In computer science, tree-traversal refers to the process of visiting (examining and/or updating) each node in a tree data structure, exactly once, in a systematic way. Such traversals are classified by the order in which the nodes are visited. The following algorithms are described for a binary tree, but they may be generalized to other trees as well.
* 1 Traversal
o 1.1 Example
o 1.2 Sample implementations
o 1.3 Level order traversal
o 1.4 Queue-based level order traversal
o 1.5 Uses
* 2 Functional traversal
* 3 Iterative traversing
* 4 See also
* 5 References
* 6 External links
Traversal
Compared to linear data structures like linked lists and one dimensional arrays, which have only one logical means of traversal, tree structures can be traversed in many different ways. Starting at the root of a binary tree, there are three main steps that can be performed and the order in which they are performed define the traversal type. These steps (in no particular order) are: performing an action on the current node (referred to as "visiting" the node), traversing to the left child node, and traversing to the right child node. Thus the process is most easily described through recursion.
To traverse a non-empty binary tree in preorder, perform the following operations recursively at each node, starting with the root node:
1. Visit the root.
2. Traverse the left subtree.
3. Traverse the right subtree.
(This is also called Depth-first traversal.)
To traverse a non-empty binary tree in inorder, perform the following operations recursively at each node, starting with the root node:
1. Traverse the left subtree.
2. Visit the root.
3. Traverse the right subtree.
(This is also called Symmetric traversal.)
To traverse a non-empty binary tree in postorder, perform the following operations recursively at each node, starting with the root node:
1. Traverse the left subtree.
2. Traverse the right subtree.
3. Visit the root.
Finally, trees can also be traversed in level-order, where we visit every node on a level before going to a lower level. This is also called Breadth-first traversal.
Example
A sorted binary tree
In this binary search tree,
* Preorder traversal sequence: F, B, A, D, C, E, G, I, H
* Inorder traversal sequence: A, B, C, D, E, F, G, H, I
o Note that the inorder traversal of this binary search tree yields an ordered list
* Postorder traversal sequence: A, C, E, D, B, H, I, G, F
* Level-order traversal sequence: F, B, G, A, D, I, C, E, H
Sample implementations
preorder(node)
print node.value
if node.left ≠null then preorder(node.left)
if node.right ≠null then preorder(node.right)
inorder(node)
if node.left ≠null then inorder(node.left)
print node.value
if node.right ≠null then inorder(node.right)
postorder(node)
if node.left ≠null then postorder(node.left)
if node.right ≠null then postorder(node.right)
print node.value
All sample implementations will require stack space proportional to the height of the tree. In a poorly balanced tree, this can be quite considerable.
We can remove the stack requirement by maintaining parent pointers in each node, or by threading the tree. In the case of using threads, this will allow for greatly improved inorder traversal, although retrieving the parent node required for preorder and postorder traversal will be slower than a simple stack based algorithm.
To traverse a threaded tree inorder, we could do something like this:
inorder(node)
while hasleftchild(node) do
node = node.left
do
visit(node)
if (hasrightchild(node)) then
node = node.right
while hasleftchild(node) do
node = node.left
else
while node.parent ≠null and node = node.parent.right
node = node.parent
node = node.parent
while node ≠null
Note that a threaded binary tree will provide a means of determining whether a pointer is a child, or a thread. See threaded binary trees for more information.
Level order traversal
Level order traversal is a traversal method by which levels are visited successively starting with level 0 (the root node), and nodes are visited from left to right on each level.
This is commonly implemented using a queue data structure with the following steps (and using the tree below as an example):
Image:Binary_tree.svg
Step 1: Push the root node onto the queue (node 2):
New queue: 2- - - - - - - - - -
Step 2:
Pop the node off the front of the queue (node 2).
Push that node's left child onto the queue (node 7).
Push that node's right child onto the queue (node 5).
Output that node's value (2).
New queue: 7-5- - - - - - - - -
Output: 2
Step 3:
Pop the node off the front of the queue (node 7).
Push that node's left child onto the queue (node 2).
Push that node's right child onto the queue (node 6).
Output that node's value (7).
New queue: 5-2-6- - - - - - - -
Output: 2 7
Step 4:
Pop the node off the front of the queue (node 5).
Push that node's left child onto the queue (NULL, so take no action).
Push that node's right child onto the queue (node 9).
Output that node's value (5).
New queue: 2-6-9- - - - - - - -
Output: 2 7 5
Step 5:
Pop the node off the front of the queue (node 2).
Push that node's left child onto the queue (NULL, so take no action).
Push that node's right child onto the queue (NULL, so take no action).
Output that node's value (2).
New queue: 6-9- - - - - - - - -
Output: 2 7 5 2
Step 6:
Pop the node off the front of the queue (node 6).
Push that node's left child onto the queue (node 5).
Push that node's right child onto the queue (node 11).
Output that node's value (6).
New queue: 9-5-11- - - - - - - -
Output: 2 7 5 2 6
Step 7:
Pop the node off the front of the queue (node 9).
Push that node's left child onto the queue (node 4).
Push that node's right child onto the queue (NULL, so take no action).
Output that node's value (9).
New queue: 5-11-4- - - - - - - -
Output: 2 7 5 2 6 9
Step 8: You will notice that because the remaining nodes in the queue have no children, nothing else will be added to the queue, so the nodes will just be popped off and output consecutively (5, 11, 4). This gives the following:
Final output: 2 7 5 2 6 9 5 11 4
which is a level-order traversal of the tree.
Queue-based level order traversal
Also, listed below is pseudocode for a simple queue based level order traversal, and will require space proportional to the maximum number of nodes at a given depth. This can be as much as the total number of nodes / 2. A more space-efficient approach for this type of traversal can be implemented using an iterative deepening depth-first search.
levelorder(root)
q = empty queue
q.enqueue(root)
while not q.empty do
node := q.dequeue()
visit(node)
if node.left ≠null
q.enqueue(node.left)
if node.right ≠null
q.enqueue(node.right)
Uses
Inorder traversal
It is particularly common to use an inorder traversal on a binary search tree because this will return values from the underlying set in order, according to the comparator that set up the binary search tree (hence the name).
To see why this is the case, note that if n is a node in a binary search tree, then everything in n 's left subtree is less than n, and everything in n 's right subtree is greater than or equal to n. Thus, if we visit the left subtree in order, using a recursive call, and then visit n, and then visit the right subtree in order, we have visited the entire subtree rooted at n in order. We can assume the recursive calls correctly visit the subtrees in order using the mathematical principle of structural induction. Traversing in reverse inorder similarly gives the values in decreasing order.
Preorder traversal
Traversing a tree in preorder while inserting the values into a new tree is common way of making a complete copy of a binary search tree.
One can also use preorder traversals to get a prefix expression (Polish notation) from expression trees: traverse the expression tree preorderly. To calculate the value of such an expression: scan from right to left, placing the elements in a stack. Each time we find an operator, we replace the two top symbols of the stack with the result of applying the operator to those elements. For instance, the expression ∗ + 234, which in infix notation is (2 + 3) ∗ 4, would be evaluated like this:
Using prefix traversal to evaluate an expression tree Expression (remaining) Stack
∗ + 234
∗ + 23 4
∗ + 2 3 4
∗ + 2 3 4
∗ 5 4
Answer 20
Functional traversal
We could perform the same traversals in a functional language like Haskell using code similar to this:
data Tree a = Nil | Node (Tree a) a (Tree a)
preorder Nil = []
preorder (Node left x right) = [x] ++ (preorder left) ++ (preorder right)
postorder Nil = []
postorder (Node left x right) = (postorder left) ++ (postorder right) ++ [x]
inorder Nil = []
inorder (Node left x right) = (inorder left) ++ [x] ++ (inorder right)
Iterative traversing
All the above recursive algorithms require stack space proportional to the depth of the tree. Recursive traversal may be converted into an iterative one using various well-known methods.
A sample is shown here for postorder traversal using a visited flag:
nonrecursivepostorder (rootNode)
nodeStack.push (rootNode)
while (!nodeStack.empty())
currNode = nodeStack.last ()
if ((currNode.left != null) and (currNode.left.visited == false))
nodeStack.push (currNode.left)
else
if ((currNode.right != null) and (currNode.right.visited == false))
nodeStack.push (currNode.right)
else
print currNode.value
currNode.visited := true
nodeStack.pop ()
In this case, for each node is required to keep an additional "visited" flag, other than usual informations (value, left-child-reference, right-child-reference).
Another example is preorder traversal without using a visited flag (java):
public void traverseTree(Node root) {
Stack nodes;
nodes.push(root);
Node currentNode;
while (!nodes.isEmpty()){
currentNode = nodes.pop();
Node right = currentNode.right();
if (right != null)
nodes.push(right);
Node left = currentNode.left();
if (left != null)
nodes.push(left);
System.out.println("Node data: "+currentNode.data);
}
}
There are lots of good diagrams missing here, go to Wikipedia and search on "Tree Traversal" to see them.
So I'm having a bit of problem creating an effect I want in photoshop, and this is the best place I could think about for help.
I'm trying to create some writing on skin and want it to look as realistic as I can. To achieve this I want to set the blendingmode to Overlay, to make the skintexture appear through the numbers and lines to some extent. But as I chance to Overlay, the color of the numbers/lines change with the skintone depending on how bright it is there going from black to red instead of staying black/gray as I want it.
I'm aware that I can make the problem go away with making the entire image B/W but I want it in color.
Any input as to how I make it work as I want to, or perhaps a better way to achieve what I'm trying to?
Heel pain is a common foot problem. The pain usually occurs underneath your heel (plantar fasciitis) or just behind it, where the Achilles tendon attaches to the heel bone (Achilles tendinitis). Although the cause of heel pain often isn’t serious, the pain itself can be severe and occasionally disabling.