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Act 3 of a 3 Act #anyqs style problem using ratios and unit conversion to figure out how many regular gummy bears are in the 'World's Largest Gummy Bear'.
Credit to:
Dan Anderson (@dandersod) who originated the idea blog.recursiveprocess.com/2011/04/15/giant-gummy-bear-wcy...
John Scammell (@scamdog) who did the first 3 Act version thescamdog.wordpress.com/2011/04/21/the-giant-gummy-bear/
Dan Meyer (@ddmeyer) for his origination of the 3 Act idea and his own 3 Act version "Super Bear" of this problem mrmeyer.com/threeacts/superbear/
Act 2 of a 3 Act #anyqs style problem using ratios and unit conversion to figure out how many regular gummy bears are in the 'World's Largest Gummy Bear'.
Credit to:
Dan Anderson (@dandersod) who originated the idea blog.recursiveprocess.com/2011/04/15/giant-gummy-bear-wcy...
John Scammell (@scamdog) who did the first 3 Act version thescamdog.wordpress.com/2011/04/21/the-giant-gummy-bear/
Dan Meyer (@ddmeyer) for his origination of the 3 Act idea and his own 3 Act version "Super Bear" of this problem mrmeyer.com/threeacts/superbear/
Deception Pass
Named by Captain George Vancouver 10 June 1792. Feeling that he had been "Deceived" as to the nature of the inner waterway, Port Gardner (now Saratoga Passage) he wrote on his chart "Deception Pass." He honored Master Joseph Whidbey, who found the passage while commanding a small-boat crew of explorers, by naming the island "Whidbey"
-Historical data by Edmond S. Meany.
Velocity of currents in Deception Pass 5 to 8 knots per hour, depth varies 4 to 37 fathoms
1 Knot 6082.66 Feet; 1 Fathom 6 Feet
Placed by Ann Washington Chapter
DAR 1935
New Android app, TundraVersions unit conversion table for length. Both metric conversions and imperial conversions available.
New Android app, TundraVersions unit conversion table for volume. Both metric conversions and imperial conversions available.
This question is extracted from "University Physics with Modern Physics 15th Edition by Hugh Young (Author), Roger Freedman (Author)"
Algorithmic Solution:
Replace the unknowns with your values, and then copy and paste into WolframAlpha.com for the answer.
Starting with the definition 1 in. = 2.54 cm, find the number of (a) kilometers in mile and (b) feet in km.
Part a
( mi)((5280 ft)/(1 mi))((12 in)/(1 ft) )((2.54 cm)/(1 in))((1 m)/(100 cm))((1 km)/(1000 m))
Round to two decimal places and include units, km.
Part b
( km)((10^3 m)/(1 km))((10^2 cm)/(1 m))((1 in)/(2.54 cm))((1 ft)/(12 in))
Use scientific notation, round to two decimal places, and include units, ft.
Lesson:
Given: 1 inch (in.) = 2.54 centimeters (cm)
(a) Find the number of kilometers in 1.00 mile:
To find the number of kilometers in 1.00 mile, we need to perform a series of unit conversions:
1 mile = 5,280 feet (this is a well-known conversion)1 foot = 30.48 centimeters (since 1 foot is 12 inches, and 1 inch = 2.54 cm)Now, we can find the number of centimeters in 1.00 mile:
1 mile = 5,280 feet1 mile = 5,280 feet x 30.48 cm/foot (using the conversion factor from feet to cm)1 mile = 160,934.4 cm
Next, we'll convert centimeters to kilometers:
1 kilometer (km) = 100,000 centimeters (since 1 km = 1,000 meters, and 1 meter = 100 centimeters)
Now, let's perform the conversion:
1 mile = 160,934.4 cm1 mile = (160,934.4 cm) / (100,000 cm/km)1 mile = 1.609344 km
So, there are approximately 1.609344
jondt.com/starting-with-the-definition-1-in-2-54-cm-find-...