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Problem Statement

Given two binary strings a and b, we have to add these two strings and then return the result as a binary string. Binary string are the strings that contains only 0s and 1s.

Example

a = "11", b = "1"

"100"

a = "1010", b = "1011"

"10101"

Approach

 

For adding two binary strings we have to perform addition bit by bit. As we know addition is performed from right end moving towards left bits. Therefore we have to reverse the given strings first and then we can perform addition of its bits starting from index 0.

For storing bit addition sequence we can create a string variable res and append the sum of two bits and carry at end of the res string for each bit position. Finally we will return the res string for output.

Algorithm

 

- Reverse the given strings.

- Create an empty string and a carry variable. Initialise carry with 0.

- Now iterate over the given string in a while loop and add bit of first and second string along with carry. Now according to value of addition append the resultant bit to res string and also update the carry for next bit .

- At last we have output string but it is in reverse order because we have performed addition on reversed input string for our convenience. Therefore reverse the output string and finally return it.

 

Implementation

C++ Program for Add Binary Leetcode Solution

#include

using namespace std;

 

string addBinary(string a, string b)

{

int carry=0;

string res="";

 

reverse(a.begin(),a.

 

www.tutorialcup.com/leetcode-solutions/add-binary-leetcod...

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Problem Statement

In this problem, we are given n people labelled from 1 to n. We are also given a 2d array trust shows that trustth people trusts trustth people for each 0

 

www.tutorialcup.com/leetcode-solutions/find-the-town-judg...

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The problem Assign cookies Leetcode Solution provides with two arrays. One of the arrays represents the size of the cookies and the other represents the greediness of the children. The problem states that you are the parent of children, and you want the maximum number of children to be content. You can only give one cookie to a child. Find the maximum number of content children. Let's take a few examples first.

g = , s =

1

Explanation: We have two cookies of size 1 each, and three children with different content values. We can make only a single child content that has greediness value 1. Since the other two children require larger cookies.

 

g = , s =

2

Explanation: We can make both of the children feel content because the cookies that we have are greater or equal to the required sizes. Thus the output is 2.

Approach for Assign Cookies Leetcode Solution

The problem Assign Cookies Leetcode Solution asks us to find the maximum number of content children if we can give only a single cookie to a child. Thus the best approach is to greedily try to make the least greedy child feel content with the smallest cookie that can be used. So, to simulate this process we sort both the given arrays and try to assign the cookies to the children. If we can't assign the current cookie to the current child then we try the next cookie until we satisfy the current child. Because if we can not satisfy the current child, we cannot satisfy the next children with the current cookie.

 

www.tutorialcup.com/leetcode-solutions/assign-cookies-lee...

Problem Statement

In this problem, we have to design a parking lot. We have 3 kinds of parking spaces (big, medium and small). All these parking spaces has some fixed number of empty slots initially.

Like, in big type of space, we can place at most b cars. In small type of space, we can place at most s cars and in medium type of space, we can place m cars.

 

We are given the values b, s and m (maximum limit of all three spaces) in the constructor of the given class. Now, we have to place some cars in these spaces. The cars too are of three types big small and medium. And they can only be placed into their respective parking lot. Like small car can only be placed in small parking lot.

 

We have to find out if we can place these cars or not. For this purpose we have to create a function addCar(int type) which will return true if the car of this type can be placed or not else this will return false.

 

Example

 

, , , , ]

 

Explanation:

 

1. parkingSystem.addCar(1); // return true because there is 1 available slot for a big car

2. parkingSystem.addCar(2); // return true because there is 1 available slot for a medium car

3. parkingSystem.addCar(3); // return false because there is no available slot for a small car

4. parkingSystem.addCar(1); // return false because there is no available slot for a big car. It is already occupied.

Approach

We have to do two task here. One is to use the values given to the constructor. Another is to create function addCar().

Now,

 

www.tutorialcup.com/leetcode-solutions/design-parking-sys...

Problem Statement

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www.tutorialcup.com/leetcode-solutions/find-the-town-judg...

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Problem Statement

In this problem a string is given and we have to reverse only the vowels of this string.

Example

"hello"

"holle"

Explanation:

before reversing : "hello"

after reversing : "holle"

"leetcode"

"leotcede"

Explanation:

 

Approach 1 (Using Stack)

We just have to reverse the vowels present in input string. So we can store all the vowels in a stack in the same order from left to right. Then again we can traverse the string and for each vowel character from left to right we will replace it with the topmost value of the stack.

Algorithm

 

- Store all the vowel characters in a set.

- Create a stack and push all vowel characters present in the input string from left to right.

- Now again traverse the string for each character. If current character is vowel, replace it with the topmost character of the stack (rightmost vowel character of input string) and remove it from the stack.

- Return the converted string.

 

Implementation for Reverse Vowels of a String Leetcode Solution

C++ Program

#include

using namespace std;

 

string reverseVowels(string s) {

 

set vowels={'a','e','i','o','u','A','E','I','O','U'};

stack stack;

for(char c:s)

{

if(vowels.count(c)) stack.push(c);

}

 

for(char& c:s)

{

if(vowels.count(c))

{

c=stack.top();

stack.pop();

}

}

 

return s;

}

 

int main()

{

string s="leetcode";

cout

 

www.tutorialcup.com/leetcode-solutions/reverse-vowels-of-...

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