Pow(x, n) Leetcode Solution

The problem "Pow(x, n) Leetcode Solution" states that you are given two numbers, one of which is a floating-point number and another an integer. The integer denotes the exponent and the base is the floating-point number. We are told to find the value after evaluating the exponent over the base. The base can be negative, positive, or zero. The exponent can lie anywhere between the range of an integer. We are also given a constraint on the output. The output will be anywhere between -10000 to +10000. So, let's take a look at a few examples.

 

Example

Base: 2

Exponent: 10

Answer: 1024

Explanation: Since the value for 2^10 = 104, hence the answer. This can also be checked by repetitive multiplication of 2 10 times.

Base: 2

Exponent: -10

Answer: 0.00098

Explanation: The answer has been changed because the value of the exponent has also been changed to -10.

Brute Force Approach

The brute force approach for the problem Pow(x, n) Leetcode Solution is very simple. We need to just simulate the operation of evaluating exponents. An exponent can easily be evaluated by multiplying the base exponent number of times. So, we can easily simulate this using a loop in any of our favorite programming languages. One thing to note, is the corner cases. When either the exponent is equal to the maximum value of integer or minimum value of integer. When we have exponent as the minimum value of integer, the answer can be either 1 or 0.

 

www.tutorialcup.com/leetcode-solutions/powx-n-leetcode-so...

Done